MCAT Organic Chemistry Reactions, IR, and NMR Reference Sheet

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John Reed

Key takeaways
  • Organic chemistry is 15% of Chem/Phys and 5% of Bio/Biochem, which works out to roughly 12 questions on a 230-question exam.
  • The exam rewards recognizing functional-group reactivity and reading spectra. It does not ask you to plan a multi-step synthesis.
  • There is no reagent sheet and no calculator on test day, so the short list below is what you carry in.
  • Two orderings decide most questions: carbonyl electrophilicity and leaving-group ability, and both come from the same electron-density logic.
  • Spectroscopy items are answerable from tabulated data plus reasoning. You are never asked to draw a structure.

If you want one page of MCAT organic chemistry reactions to review the night before a full-length, this is it. Below are the mechanisms the AAMC reuses, the IR bands and proton NMR shifts that turn up as passage data, and the two reactivity orderings that settle most questions before you reach the answer choices.

It is much shorter than your organic chemistry course was, and that is the point. The MCAT tests first-semester organic chemistry, and it tests it the way a physician uses it: as the chemical logic underneath a lab workflow or an enzyme mechanism.

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How the MCAT Actually Tests Organic Chemistry

Organic chemistry appears in two of the four scored sections.

SectionOrganic chemistry shareQuestions in sectionApproximate organic questions
Chemical and Physical Foundations (Chem/Phys)15%59About 9
Biological and Biochemical Foundations (Bio/Biochem)5%59About 3
Psychological, Social, and Biological FoundationsNone590
Critical Analysis and Reasoning SkillsNone530

Discipline percentages are from the AAMC Chemical and Physical Foundations of Biological Systems section overview and the AAMC Biological and Biochemical Foundations of Living Systems section overview, verified August 28, 2026. AAMC notes these percentages are approximated to the nearest 5% and vary between test forms.

So about 12 questions total. What matters more than the count is what those 12 questions ask. Three patterns cover almost all of them:

  1. Recognize the functional group and predict what it does. Which carbon is electrophilic, what attacks it, and what leaves. A question that names a reagent and a substrate is asking you to place both in a mechanism family, not to recall a named reaction.
  2. Read spectra as constraints. IR and ¹H NMR show up as passage data you interpret, not as standalone recall. Mass spectrometry appears mostly as a molecular ion.
  3. Compare, do not calculate. Rank two acids, decide whether one base can deprotonate another, assign R or S, or say which of two carbonyls reacts faster.

What the MCAT does not do is hand you a target molecule and ask for a synthesis. Retrosynthesis, protecting-group strategy beyond acetals, aromatic substitution mechanisms, and pericyclic reactions are second-semester topics that the AAMC content outlines leave out. If you are pushing arrows through four-step sequences, you are studying for the wrong exam.

The practical version: know a short list of mechanisms cold, know the spectroscopy tables, and know the acid-base and reactivity orderings. That is the whole of it.

MCAT Organic Chemistry Reactions Sheet

No reagent list is provided on test day and no calculator is permitted. These are the reactions the AAMC reuses, grouped by the mechanism that drives them.

Substitution and Elimination

ReactionReagents and conditionsSubstrateProductMechanism note
SN2Strong nucleophile (CN⁻, N₃⁻, RS⁻, I⁻, HO⁻) in polar aprotic solvent (DMSO, DMF, acetone)Methyl or primary alkyl halideSubstitution product with inverted configurationOne concerted step, backside attack; rate = k[RX][Nu]; sterics dominate, so tertiary substrates are inert
SN1Weak nucleophile, polar protic solvent (H₂O, ROH), heatTertiary, allylic, or benzylic halideSubstitution product, largely racemizedTwo steps through a planar carbocation; rate = k[RX]; carbocation rearrangements are possible
E2Strong base (NaOEt, NaOH, NaNH₂; KOtBu for bulky), heatSecondary or tertiary alkyl halideAlkene — Zaitsev (more substituted) unless the base is bulky, which gives HofmannConcerted; requires the H and the leaving group anti-periplanar; rate = k[RX][base]
E1Weak base, polar protic solvent, heatTertiary alkyl halideAlkene (Zaitsev)Same carbocation as SN1 and always competes with it

Oxidation and Reduction

ReactionReagents and conditionsSubstrateProductMechanism note
Mild oxidationPCC in anhydrous CH₂Cl₂ (also Swern, Dess-Martin)Primary alcoholAldehydeAnhydrous, so no hydrate forms and oxidation stops cleanly
Strong oxidationH₂CrO₄ / Jones, K₂Cr₂O₇/H⁺, hot KMnO₄Primary alcoholCarboxylic acidProceeds through the aldehyde hydrate, which supplies the extra C–H that is oxidized
OxidationAny of the aboveSecondary alcoholKetoneCannot over-oxidize; a tertiary alcohol has no carbinol C–H and does not react
Mild reductionNaBH₄ in MeOH or EtOHAldehyde, ketonePrimary or secondary alcoholHydride adds to the carbonyl carbon; too mild for esters, acids, or amides
Strong reductionLiAlH₄, then H₃O⁺ workupAldehyde, ketone, ester, carboxylic acid, amideAlcohol (amide gives an amine)Powerful hydride source; reacts violently with any protic solvent
Thiol oxidationMild oxidant (O₂, I₂)2 R–SHDisulfide R–S–S–RThe redox switch behind cysteine and cystine in proteins

Nucleophilic Addition to the Carbonyl

ReactionReagents and conditionsSubstrateProductMechanism note
Grignard additionRMgBr or RLi, then H₃O⁺Aldehyde, ketone, esterSecondary or tertiary alcoholCarbanion-like carbon adds to the carbonyl carbon, forming a new C–C bond; destroyed by water, alcohols, or any acidic proton
Cyanohydrin formationHCN or NaCN / H⁺Aldehyde, ketoneCyanohydrin (α-hydroxy nitrile)Reversible addition of cyanide; the nitrile can be hydrolyzed onward to a carboxylic acid
HydrationH₂O, acid or base catalysisAldehyde, ketoneGeminal diol (hydrate)Reversible; the equilibrium favors the hydrate only for very electrophilic carbonyls such as formaldehyde
Acetal formation2 ROH, catalytic H⁺, remove waterAldehyde, ketoneAcetal (ketal)Passes through the hemiacetal; used as a protecting group and reversed by aqueous acid
Imine (Schiff base) formationPrimary amine RNH₂, catalytic H⁺, optimum around pH 4–5Aldehyde, ketoneImine (C=N)Addition gives a carbinolamine, then acid-catalyzed dehydration; too much acid protonates the amine and kills the nucleophile
Enamine formationSecondary amine R₂NH, catalytic H⁺Aldehyde, ketoneEnamine (N–C=C)Same route as an imine, but with no N–H left the iminium must lose an α-proton instead

Enol, Enolate, and Alpha-Carbon Chemistry

ReactionReagents and conditionsSubstrateProductMechanism note
Keto-enol tautomerizationTrace acid or baseCarbonyl with an α-HEnol (usually minor at equilibrium)Constitutional isomers, not resonance forms — a proton physically moves
Aldol additionDilute NaOH, room temperature (or an aldolase enzyme)Two aldehyde or ketone units, at least one with an α-Hβ-hydroxy carbonylEnolate α-carbon attacks the other carbonyl carbon; fully reversible as a retro-aldol
Aldol condensationNaOH, heatThe β-hydroxy carbonyl aboveα,β-unsaturated carbonylE1cb dehydration after the addition; driven by the stability of the conjugated product
DecarboxylationHeat, no reagent requiredβ-keto acid or β-diacid (malonic)Product with one fewer carbon, plus CO₂Six-membered cyclic transition state; requires a carbonyl β to the COOH; gives an enol that tautomerizes

Carboxylic Acid Derivatives (Nucleophilic Acyl Substitution)

ReactionReagents and conditionsSubstrateProductMechanism note
Fischer esterificationExcess ROH, catalytic H₂SO₄, heatCarboxylic acidEster + H₂OReversible; drive forward with excess alcohol or by removing water
Acidic ester hydrolysisH₃O⁺, heat, excess waterEsterCarboxylic acid + alcoholExactly the reverse of Fischer esterification, and equally reversible
SaponificationNaOH, heat, then H₃O⁺ workupEsterCarboxylate salt + alcoholIrreversible — the carboxylate is deprotonated and no longer electrophilic; the basis of soap making and of triacylglycerol cleavage
Amide hydrolysisH₃O⁺ or HO⁻, heat, prolongedAmideCarboxylic acid + amineThe slowest acyl substitution; peptide bonds are amides, which is why they are kinetically stable in water
TransesterificationDifferent alcohol, acid or base catalysisEsterNew ester + original alcoholEquilibrium controlled by which alcohol is in excess

Reactivity order of the derivatives — memorize this ranking, since it decides which interconversions are possible:

acid chloride greater than anhydride greater than ester ≈ carboxylic acid greater than amide greater than carboxylate

A more reactive derivative converts to a less reactive one directly. Going the other direction requires an activating step. The ranking tracks leaving-group ability and how strongly the attached heteroatom donates electron density back into the carbonyl.

Functional Group Reactivity: The Two Orderings That Decide Everything

Most organic questions on the MCAT are comparisons, and almost every comparison reduces to one of two rankings.

Which Carbonyls Are Most Electrophilic

A carbonyl carbon is electrophilic because oxygen pulls electron density off it. Anything that gives that density back makes the carbon less positive and less reactive. Two effects do the giving:

  • Resonance donation from the attached heteroatom. A lone pair on the atom bonded to the carbonyl carbon delocalizes into the C=O. Nitrogen donates strongly, oxygen moderately, chlorine barely at all, since its lone pairs sit in a 3p orbital that overlaps poorly with carbon's 2p. This is the dominant term, and it is why an amide is the least reactive derivative and an acid chloride the most.
  • Donation from alkyl groups. Alkyl substituents push a little density toward the carbonyl carbon and get in the way sterically. A ketone has two, an aldehyde has one, so aldehydes are more electrophilic than ketones.

Together they give the ordering in the acyl substitution table above: acid chloride, anhydride, ester ≈ carboxylic acid, amide, carboxylate. That series ranks the derivatives for nucleophilic acyl substitution, where the nucleophile adds and a leaving group departs. Aldehydes and ketones sit outside it because they have no leaving group and cannot substitute at all. For pure addition, the order is acid chloride, anhydride, aldehyde, ketone, ester, amide. Same logic, both times.

A carboxylate is not electrophilic at all: its charge is delocalized over both oxygens. That is exactly why saponification is irreversible.

Leaving-Group Ability

A good leaving group is a weak base, meaning it holds a negative charge comfortably. The proxy is the pKa of its conjugate acid, and lower is better.

Leaving groupConjugate acidApproximate pKa of conjugate acidVerdict
I⁻HI−10Excellent
Br⁻HBr−9Excellent
Cl⁻HCl−7Good
TsO⁻ (tosylate)TsOH≈ −2.8Excellent
H₂O (from a protonated alcohol)H₃O⁺−1.7Good
RCOO⁻ (carboxylate)RCOOH≈ 4.8Fair
HO⁻H₂O15.7Poor
RO⁻ (alkoxide)ROH≈ 16Poor
R₂N⁻ (amide nitrogen)R₂NH≈ 38Very poor

Set that next to the acyl reactivity series and you will see they are the same list. Chloride leaves easily, so acid chlorides are reactive. Alkoxide leaves reluctantly, so esters are sluggish. An amide nitrogen is essentially never expelled as an anion, which is why peptide bonds survive in water for years. One honest exception: fluoride looks respectable by pKa (HF is about 3.2) but leaves poorly, because C–F is the strongest single bond carbon makes. The proxy is a heuristic, not a law.

This also explains why hydroxide never departs a carboxylic acid directly. To esterify an acid you protonate the OH first, turning a terrible leaving group into water. Every acid-catalyzed carbonyl mechanism is running some version of that trick.

The pKa Comparisons the Exam Reuses

You are almost never asked for an absolute value. You are asked whether one species can deprotonate another, and the reaction proceeds if the acid being deprotonated is stronger than the conjugate acid that forms.

SpeciesApproximate pKaWhat it shows
Protonated amide (conjugate acid of acetamide)roughly −8 to +0.5Amides are very weak bases
Trichloroacetic acid≈ 0.7Three chlorines, maximum inductive pull
Dichloroacetic acid≈ 1.29 (sources give 1.29–1.35)Two chlorines
Chloroacetic acid≈ 2.86One chlorine
Acetic acid4.76The baseline, no halogen
Amino acid α-carboxyl≈ 2Lowered by the nearby ammonium
Protonated aniline≈ 4.6Lone pair tied up in the ring
Ammonium (NH₄⁺)9.25
Amino acid α-ammonium≈ 9–10
Phenol≈ 10Resonance-stabilized conjugate base
Protonated alkylamine≈ 10–11The strongest common organic base on the exam
Water15.7
Ethanol≈ 16
Terminal alkyne C–H≈ 25sp carbon holds the pair closest in
Alkane C–H≈ 50Effectively not acidic

The chloroacetic series shows the inductive effect adding up with each halogen. The basicity ordering, alkylamine then ammonia then aniline then amide, is one of the AAMC's favorite comparisons because it lets a passage ask about a protein side chain without naming a mechanism.

Treat the amide entry as a range rather than a figure. Published values for the conjugate acid of acetamide run from about −8 for the nitrogen-protonated form to roughly 0 for the oxygen-protonated form, and textbooks quote one or the other without always saying which. The qualitative conclusion is what gets tested and it is not in doubt: an amide nitrogen is a far weaker base than an amine nitrogen, because its lone pair is delocalized into the carbonyl. The dichloroacetic acid value is similarly approximate.

MCAT IR Absorption Reference

The exam almost never asks you to interpret a full IR spectrum. It hands you one or two bands and asks what they rule in or out. Intensity and shape matter as much as position.

BondWavenumber (cm⁻¹)Appearance and notes
O–H, alcohol3200–3600Strong, broad and rounded from hydrogen bonding
O–H, carboxylic acid2500–3300Very broad, overlaps and obscures the C–H region; caused by the hydrogen-bonded dimer
N–H, amine or amide3300–3500Medium, sharper than O–H; a primary amine gives two bands, a secondary amine gives one
C–H, sp (terminal alkyne)~3300Sharp and strong; distinguishes a terminal from an internal alkyne
C–H, sp² (alkene, aromatic)3000–3100Medium; just to the left of 3000
C–H, sp³ (alkyl)2850–3000Strong; present in nearly every organic compound, so rarely diagnostic
C–H, aldehyde2700–2900Two weak bands near 2720 and 2820; highly diagnostic for an aldehyde
C≡N, nitrile2220–2260Strong and sharp; strong because the C–N triple bond is highly polarized
C≡C, alkyne2100–2260Weak, and absent entirely in a symmetric internal alkyne
C=O, acid chloride1780–1815Strong; the highest carbonyl on the exam
C=O, anhydride1740–1830Strong, appears as two bands
C=O, ester1735–1750Strong
C=O, aldehyde1720–1740Strong; confirm with the 2720/2820 C–H doublet
C=O, ketone1705–1725Strong; the reference point for all carbonyl comparisons
C=O, carboxylic acid1700–1725Strong; the dimer typically lands near 1710
C=O, amide1630–1690Strong; lowest of the common carbonyls because the nitrogen donates electron density into the C=O
C=C, alkene1620–1680Weak to medium
C=C, aromatic ring1450–1600Several medium bands
C–O, alcohol or ether1000–1300Strong, but in the crowded fingerprint region

Two patterns explain nearly every carbonyl question. Conjugation lowers the C=O frequency by roughly 20–40 cm⁻¹, because delocalization gives the bond partial single-bond character — an α,β-unsaturated ketone sits near 1680 rather than 1715. Ring strain raises it, which is why a cyclopentanone absorbs near 1745 and a cyclobutanone near 1780.

Two-panel IR absorption chart showing the X-H and triple bond region from 3700 to 2100 wavenumbers and a zoomed carbonyl region from 1840 to 1600, with each bond drawn as a band across its absorption range The carbonyl region is drawn on its own scale because the exam separates those bands by as little as 15 wavenumbers.

MCAT ¹H NMR Chemical Shift Reference

Chemical shift is set by shielding: electron density near a proton shields it and moves the signal upfield toward 0 ppm, while nearby electronegative atoms or π systems deshield it and move it downfield.

Proton environmentδ (ppm)Notes
Tetramethylsilane (TMS)0The internal reference standard
R–CH₃0.8–1.0Most upfield of the ordinary alkyl signals
R–CH₂–R1.2–1.4
R₃C–H (methine)1.4–1.7
C=C–C–H (allylic)1.6–2.6Weakly deshielded by the adjacent π system
C≡C–H (alkyne)1.7–2.8Anomalously upfield for an sp C–H, due to ring-current shielding
O=C–C–H (α to a carbonyl)2.0–2.5The acetyl methyl of a ketone sits near 2.1
Ar–C–H (benzylic)2.2–2.8
N–C–H (amine)2.2–2.9
R–NH₂ / R₂NH0.5–5.0Broad, variable, exchangeable with D₂O
R–CH₂–I3.1–3.3
R–CH₂–Br3.3–3.6
R–CH₂–Cl3.4–3.8Deshielding tracks halogen electronegativity
R–CH₂–O–R (ether, alcohol)3.3–4.0
R–CH₂–O–C=O (ester alkoxy)3.7–4.8Ethyl acetate's OCH₂ quartet sits at 4.12
R–OH (alcohol)0.5–5.0Broad, concentration dependent, exchangeable
C=C–H (vinyl)4.6–6.0
Ar–OH (phenol)4.0–8.0Broad and highly variable, exchangeable
Ar–H (aromatic)6.5–8.0Strongly deshielded by the aromatic ring current
R–CONH–R (amide N–H)5.0–9.0Broad, exchangeable
R–CHO (aldehyde)9.0–10.0Unmistakable; nothing else appears there
R–COOH (carboxylic acid)10.0–13.0The most downfield common signal, broad and exchangeable

Three rules turn a shift table into answers:

  1. Integration counts protons. The area under a signal is proportional to the number of hydrogens producing it, giving you a ratio, not an absolute count.
  2. Multiplicity counts neighbors. The n + 1 rule: a signal split into six lines has five protons on adjacent carbons. Forgetting the plus one is the most common NMR error on the exam.
  3. Exchangeable protons do not split their neighbors and vanish on a D₂O shake. O–H and N–H protons exchange too fast to couple, which is why a carboxylic acid proton appears as a broad singlet rather than a multiplet.

Worked Example: From a Formula, One IR Band, and a Splitting Pattern to a Structure

This is the shape an MCAT spectroscopy item takes: a molecular formula, one or two IR bands, a short NMR table, four candidate structures. Here is the order to attack it in.

The data. An unknown liquid has molecular formula C₄H₈O. Its IR shows a strong band at 1715 cm⁻¹, nothing between 3100 and 3600 cm⁻¹, and no bands between 2700 and 2900 cm⁻¹ beyond ordinary alkyl C–H. Its ¹H NMR shows δ 2.45 (2H, quartet), δ 2.13 (3H, singlet), δ 1.05 (3H, triplet).

Step 1. Count degrees of unsaturation. For C₄H₈O that is (2 × 4 + 2 − 8) / 2 = 1. Oxygen does not enter the formula. One degree means exactly one ring or one π bond and nothing more.

Step 2. Spend the degree using the IR. A strong band at 1715 cm⁻¹ is in the ketone window. A clean 3100–3600 region rules out an alcohol (3200–3600, broad), and the absence of a very broad 2500–3300 envelope rules out a carboxylic acid. No 2720/2820 pair rules out an aldehyde. So the single degree of unsaturation is a ketone carbonyl, not a ring and not an alkene.

Step 3. Check the integration closes. The 2:3:3 ratio sums to 8 protons, matching C₄H₈O exactly. Every hydrogen is accounted for, so there is no hidden exchangeable proton, which independently confirms there is no O–H.

Step 4. Read the splitting for connectivity. A 2H quartet needs three neighbors and a 3H triplet needs two, so those two are a CH₃CH₂ group coupled to each other. Place them by shift: the CH₂ at δ 2.45 sits in the 2.0–2.5 window for a proton α to a carbonyl, not at 3.3–4.0 where a CH₂ on oxygen would land. So the ethyl is bonded to the carbonyl carbon, not to an oxygen. The 3H singlet at δ 2.13 has no neighbors at all and sits in the same α window, so it is a methyl bonded straight to C=O.

Step 5. Assemble and verify. A carbonyl flanked by ethyl and methyl is CH₃COCH₂CH₃, butan-2-one. Four carbons, eight hydrogens, one oxygen. It closes.

Step 6. Kill the alternatives out loud.

CandidateWhy the data exclude it
ButanalWould show a 1H signal at δ 9.0–10.0 and the diagnostic 2720/2820 C–H doublet. Neither is present.
2-MethylpropanalSame aldehyde objections, and it would give a 6H doublet rather than a 3H singlet.
TetrahydrofuranSpends its one degree of unsaturation on a ring, leaving nothing to explain 1715 cm⁻¹.
But-3-en-1-olNeeds a broad O–H near 3300 and vinyl protons at δ 4.6–6.0, and its exchangeable proton would break the 2:3:3 integration.

No drawing, no arrow pushing. Degrees of unsaturation set the budget, IR spends it, integration confirms the formula, splitting supplies the connectivity. Run those four moves in that order and the timing takes care of itself.

What Spectroscopy Questions Actually Require

Worth being clear about the limits, because students overprepare this in one direction and underprepare it in another.

Every MCAT spectroscopy question is answerable from tabulated data and reasoning. You are never asked to draw a structure, propose a mechanism from a spectrum, or interpret ¹³C multiplicity, coupling constants, or a full fingerprint region. The passage hands you the bands and shifts it wants used.

What you do need is the ability to use a value as an exclusion. A very broad 2500–3300 absorption next to a band near 1710 does not merely suggest a carboxylic acid, it eliminates ketones, esters, and alcohols in one step. IR eliminates, NMR identifies, and the molecular formula keeps both honest. The tables above are ranges on purpose: real spectra shift with solvent, concentration, and hydrogen bonding, and the AAMC writes items so the answer sits comfortably inside a range. If you are deciding between two choices on a 5 cm⁻¹ difference, you have misread the question.

How to Drill This

Reading a reference sheet is not the same as recalling it under a 95-second clock. Once you can reproduce the carbonyl ordering and the handful of diagnostic IR bands from memory, put them under exam conditions with our free MCAT organic chemistry practice questions, which run 25 items in the AAMC interface with full worked solutions. The rest of that section is covered by our MCAT general chemistry practice questions and MCAT physics practice questions. For the wider picture, see how hard the MCAT is or our roundup of free MCAT resources.

Frequently Asked Questions

Which MCAT organic chemistry reactions do I actually need to know?

The ones in the sheet above and essentially nothing beyond them: SN1, SN2, E1, E2, alcohol oxidation and carbonyl reduction, Grignard addition, imine and enamine formation, acetal protection, keto-enol tautomerization, aldol addition and condensation, decarboxylation, and the acyl substitutions. The list is short because the AAMC specifies first-semester organic chemistry only.

What are the reactions to know if I only have a few days?

Triage to the carbonyl. Nucleophilic addition and nucleophilic acyl substitution, plus the reactivity ordering that governs both, account for more MCAT organic questions than any other topic, and they carry straight into biochemistry through aldolase, transamination, and thioester chemistry. Spectroscopy comes second because it pays back study time faster than anything else. Substitution and elimination come third.

Do I need to memorize IR wavenumbers exactly?

No. Learn a few anchors and two rules. Anchors: alcohol O–H broad at 3200–3600, carboxylic acid O–H very broad at 2500–3300, ketone C=O near 1715, ester near 1740, amide near 1650. Rules: conjugation lowers a C=O by roughly 20–40 cm⁻¹, ring strain raises it. You can reason to the rest.

Is second-semester organic chemistry tested?

No. Aromatic substitution mechanisms, pericyclic reactions, named multi-step syntheses, and retrosynthetic analysis fall outside the AAMC content outlines. If your course covered them, set them aside for this exam.

Do I have to draw or identify structures?

The exam does show structures, but much of the reasoning is verbal: comparing pKa values, choosing a mechanism family, ranking CIP priorities, reading tabulated spectra. You are never asked to produce a drawing.

MCAT Reference Sheets

The rest of the high-yield memorization set:

MCAT amino acid chart · MCAT equation sheet · MCAT hormone chart

Then test what stuck with our free MCAT practice questions — 25 questions per subject in the AAMC test interface, with full worked solutions.

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